What are the solutions to the equation a^2-a=0 ?

The solutions to the equation a^2-a=0 are a=1,a=0

Find the zeros of a^2-a=0

The zeros of a^2-a=0 are a=1,a=0

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a^{2} - a = 0

a = 1, a = 0

Solution steps

a^{2} - a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

a_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

a = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

a = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 1, a = 0

x^{2} + 5 x + 25

lo g_{4} (x) < 3

\frac{- 8}{6}

\frac{x}{- 3} - 3 \leq - 2

- 2 x + 6 \geq 3 x - 34

What are the solutions to the equation a^2-a=0 ?
The solutions to the equation a^2-a=0 are a=1,a=0
Find the zeros of a^2-a=0
The zeros of a^2-a=0 are a=1,a=0