What are the solutions to the equation x^2+x-2450=0 ?

The solutions to the equation x^2+x-2450=0 are x=49,x=-50

Find the zeros of x^2+x-2450=0

The zeros of x^2+x-2450=0 are x=49,x=-50

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x^{2} + x - 2450 = 0

x = 49, x = - 50

Solution steps

x^{2} + x - 2450 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2450 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2450) = 99

x_{1, 2} = \frac{- 1 \pm 99}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 99}{2 \cdot 1}, x_{2} = \frac{- 1 - 99}{2 \cdot 1}

x = \frac{- 1 + 99}{2 \cdot 1} : 49

x = \frac{- 1 - 99}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

x = 49, x = - 50

- 6 x^{3} + 3 x^{2} + 18 x

5 x - 9 = 3 (x - 2)

20 x < 4

- 5 - \frac{t}{6} \geq - 9

\frac{x}{5} < \frac{2}{10}

What are the solutions to the equation x^2+x-2450=0 ?
The solutions to the equation x^2+x-2450=0 are x=49,x=-50
Find the zeros of x^2+x-2450=0
The zeros of x^2+x-2450=0 are x=49,x=-50