What is factor (2x+2)^4-(x+1)^5 ?

The solution to factor (2x+2)^4-(x+1)^5 is (x+1)^4(-x+15)

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factor (2x+2)^4-(x+1)^5

factor

(2 x + 2)^{4} - (x + 1)^{5}

(x + 1)^{4} (- x + 15)

Solution steps

(2 x + 2)^{4} - (x + 1)^{5}

Factor

(2 x + 2)^{4} : 16 (x + 1)^{4}

= 16 (x + 1)^{4} - (x + 1)^{5}

Factor out common term

(x + 1)^{4} : (x + 1)^{4} (16 - (x + 1))

= (x + 1)^{4} (16 - (x + 1))

Expand

16 - (x + 1) : - x + 15

= (x + 1)^{4} (- x + 15)

∣ 2 x - 5 ∣ = 3 x

10 \cdot (- 6 - 9 i)

3 x^{2} + 12 x = 0

155 \cdot \frac{π}{180}

(\frac{- 4}{5}) + \frac{1}{8}

What is factor (2x+2)^4-(x+1)^5 ?
The solution to factor (2x+2)^4-(x+1)^5 is (x+1)^4(-x+15)