What are the solutions to the equation 12x^2-7x-12=0 ?

The solutions to the equation 12x^2-7x-12=0 are x= 4/3 ,x=-3/4

Find the zeros of 12x^2-7x-12=0

The zeros of 12x^2-7x-12=0 are x= 4/3 ,x=-3/4

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12 x^{2} - 7 x - 12 = 0

x = \frac{4}{3}, x = - \frac{3}{4}

Decimal Notation

x = 1.33333 \dots, x = - 0.75

Solution steps

12 x^{2} - 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 12 ( - 12 )}{2 \cdot 12}

(- 7)^{2} - 4 \cdot 12 (- 12) = 25

x_{1, 2} = \frac{- ( - 7 ) \pm 25}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 25}{2 \cdot 12}, x_{2} = \frac{- ( - 7 ) - 25}{2 \cdot 12}

x = \frac{- ( - 7 ) + 25}{2 \cdot 12} : \frac{4}{3}

x = \frac{- ( - 7 ) - 25}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{3}{4}

\frac{3 ^{2}}{3 ^{5}}

2 x^{2} + 5 x - 2 = 3 x (5 x + 2)

\frac{1}{3} (2 x - \frac{3}{7}) + \frac{1}{6} x = \frac{4}{7}

36 a^{2} - 121

- x^{2} + x + 6

What are the solutions to the equation 12x^2-7x-12=0 ?
The solutions to the equation 12x^2-7x-12=0 are x= 4/3 ,x=-3/4
Find the zeros of 12x^2-7x-12=0
The zeros of 12x^2-7x-12=0 are x= 4/3 ,x=-3/4