What are the solutions to the equation 4x^2=4x-1 ?

The solutions to the equation 4x^2=4x-1 are x= 1/2

Find the zeros of 4x^2=4x-1

The zeros of 4x^2=4x-1 are x= 1/2

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4 x^{2} = 4 x - 1

x = \frac{1}{2}

Solution steps

4 x^{2} = 4 x - 1

Move

1

to the left side

4 x^{2} + 1 = 4 x

Move

4 x

to the left side

4 x^{2} + 1 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

\frac{11}{12} = \frac{3}{8} + v

x^{2} + 8 x - 33

12 = \frac{2}{5} (9 x + 25)

(2 x - 9)^{4} (x - 1)^{3} (x + 1) \leq 0

0 = 15 t - 1.86 t^{2}

What are the solutions to the equation 4x^2=4x-1 ?
The solutions to the equation 4x^2=4x-1 are x= 1/2
Find the zeros of 4x^2=4x-1
The zeros of 4x^2=4x-1 are x= 1/2