What are the solutions to the equation 15x^2-50=-19x ?

The solutions to the equation 15x^2-50=-19x are x=(-19+sqrt(3361))/(30),x=(-19-sqrt(3361))/(30)

Find the zeros of 15x^2-50=-19x

The zeros of 15x^2-50=-19x are x=(-19+sqrt(3361))/(30),x=(-19-sqrt(3361))/(30)

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15 x^{2} - 50 = - 19 x

x = \frac{- 19 + 3361}{30}, x = \frac{- 19 - 3361}{30}

Decimal Notation

x = 1.29913 \dots, x = - 2.56580 \dots

Solution steps

15 x^{2} - 50 = - 19 x

Move

19 x

to the left side

15 x^{2} - 50 + 19 x = 0

Write in the standard form

a x^{2} + b x + c = 0

15 x^{2} + 19 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 15 ( - 50 )}{2 \cdot 15}

1 9^{2} - 4 \cdot 15 (- 50) = 3361

x_{1, 2} = \frac{- 19 \pm 3361}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 19 + 3361}{2 \cdot 15}, x_{2} = \frac{- 19 - 3361}{2 \cdot 15}

x = \frac{- 19 + 3361}{2 \cdot 15} : \frac{- 19 + 3361}{30}

x = \frac{- 19 - 3361}{2 \cdot 15} : \frac{- 19 - 3361}{30}

The solutions to the quadratic equation are:

x = \frac{- 19 + 3361}{30}, x = \frac{- 19 - 3361}{30}

52 - 3 x < - 14

- 30 + k = 22

lo g_{12} (9) + 2 lo g_{12} (4)

- 5 x + 4 \geq - 36

4 x^{2} - x - 14 \leq 0

What are the solutions to the equation 15x^2-50=-19x ?
The solutions to the equation 15x^2-50=-19x are x=(-19+sqrt(3361))/(30),x=(-19-sqrt(3361))/(30)
Find the zeros of 15x^2-50=-19x
The zeros of 15x^2-50=-19x are x=(-19+sqrt(3361))/(30),x=(-19-sqrt(3361))/(30)