What are the solutions to the equation 2p^2+4p-5=0 ?

The solutions to the equation 2p^2+4p-5=0 are p=(-2+sqrt(14))/2 ,p=-(2+sqrt(14))/2

Find the zeros of 2p^2+4p-5=0

The zeros of 2p^2+4p-5=0 are p=(-2+sqrt(14))/2 ,p=-(2+sqrt(14))/2

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2 p^{2} + 4 p - 5 = 0

p = \frac{- 2 + 14}{2}, p = - \frac{2 + 14}{2}

Decimal Notation

p = 0.87082 \dots, p = - 2.87082 \dots

Solution steps

2 p^{2} + 4 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 5) = 214

p_{1, 2} = \frac{- 4 \pm 2 14}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 4 + 2 14}{2 \cdot 2}, p_{2} = \frac{- 4 - 2 14}{2 \cdot 2}

p = \frac{- 4 + 2 14}{2 \cdot 2} : \frac{- 2 + 14}{2}

p = \frac{- 4 - 2 14}{2 \cdot 2} : - \frac{2 + 14}{2}

The solutions to the quadratic equation are:

p = \frac{- 2 + 14}{2}, p = - \frac{2 + 14}{2}

2^{15}

(- \frac{3}{2})^{2} + 2 (- \frac{3}{2})

2 (t + 2) - 3 t \geq - 1

- 2 x^{2} - x + 10

\frac{w ^{8}}{w ^{2}}

What are the solutions to the equation 2p^2+4p-5=0 ?
The solutions to the equation 2p^2+4p-5=0 are p=(-2+sqrt(14))/2 ,p=-(2+sqrt(14))/2
Find the zeros of 2p^2+4p-5=0
The zeros of 2p^2+4p-5=0 are p=(-2+sqrt(14))/2 ,p=-(2+sqrt(14))/2