What is factor-49b^{12}+a^{10} ?

The solution to factor-49b^{12}+a^{10} is (a^5+7b^6)(a^5-7b^6)

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factor-49b^{12}+a^{10}

factor

- 49 b^{12} + a^{10}

(a^{5} + 7 b^{6}) (a^{5} - 7 b^{6})

Solution steps

- 49 b^{12} + a^{10}

= a^{10} - 49 b^{12}

a^{10} = (a^{5})^{2}

49 b^{12} = (7 b^{6})^{2}

= (a^{5})^{2} - (7 b^{6})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{5})^{2} - (7 b^{6})^{2} = (a^{5} + 7 b^{6}) (a^{5} - 7 b^{6})

= (a^{5} + 7 b^{6}) (a^{5} - 7 b^{6})

\frac{4 x ^{- 2} ( yz ) ^{- 1}}{2 ^{3} x ^{4} y}

\frac{x ^{- 5}}{x ^{4}}

2 x^{2} + 2 x + 6 = 0

(2 x^{4} y^{- 3})^{- 1}

(b - \frac{1}{2})^{4}

What is factor-49b^{12}+a^{10} ?
The solution to factor-49b^{12}+a^{10} is (a^5+7b^6)(a^5-7b^6)