What are the solutions to the equation -3x^2-2x+7=0 ?

The solutions to the equation -3x^2-2x+7=0 are x=-(1+sqrt(22))/3 ,x=(sqrt(22)-1)/3

Find the zeros of -3x^2-2x+7=0

The zeros of -3x^2-2x+7=0 are x=-(1+sqrt(22))/3 ,x=(sqrt(22)-1)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 2 x + 7 = 0

x = - \frac{1 + 22}{3}, x = \frac{22 - 1}{3}

Decimal Notation

x = - 1.89680 \dots, x = 1.23013 \dots

Solution steps

- 3 x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) \cdot 7}{2 ( - 3 )}

(- 2)^{2} - 4 (- 3) \cdot 7 = 222

x_{1, 2} = \frac{- ( - 2 ) \pm 2 22}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 22}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 2 22}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 2 22}{2 ( - 3 )} : - \frac{1 + 22}{3}

x = \frac{- ( - 2 ) - 2 22}{2 ( - 3 )} : \frac{22 - 1}{3}

The solutions to the quadratic equation are:

x = - \frac{1 + 22}{3}, x = \frac{22 - 1}{3}

(x - 3)^{\frac{7}{2}} - 9 (x - 3)^{\frac{3}{2}}

\frac{x + 2}{x + 3} < 0

a^{2} - b^{2} + 4 a - 4 b

r > 15 - 2 r

2 x^{2} - 17 x + 8

What are the solutions to the equation -3x^2-2x+7=0 ?
The solutions to the equation -3x^2-2x+7=0 are x=-(1+sqrt(22))/3 ,x=(sqrt(22)-1)/3
Find the zeros of -3x^2-2x+7=0
The zeros of -3x^2-2x+7=0 are x=-(1+sqrt(22))/3 ,x=(sqrt(22)-1)/3