What are the solutions to the equation -5x(x+6)=4(x-3)-10 ?

The solutions to the equation -5x(x+6)=4(x-3)-10 are x=-(17+sqrt(399))/5 ,x=(sqrt(399)-17)/5

Find the zeros of -5x(x+6)=4(x-3)-10

The zeros of -5x(x+6)=4(x-3)-10 are x=-(17+sqrt(399))/5 ,x=(sqrt(399)-17)/5

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- 5 x (x + 6) = 4 (x - 3) - 10

x = - \frac{17 + 399}{5}, x = \frac{399 - 17}{5}

Solution steps

- 5 x (x + 6) = 4 (x - 3) - 10

Expand

- 5 x (x + 6) : - 5 x^{2} - 30 x

Expand

4 (x - 3) - 10 : 4 x - 22

- 5 x^{2} - 30 x = 4 x - 22

Move

22

to the left side

- 5 x^{2} - 30 x + 22 = 4 x

Move

4 x

to the left side

- 5 x^{2} - 34 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 34 ) \pm ( - 34 ) ^{2} - 4 ( - 5 ) \cdot 22}{2 ( - 5 )}

(- 34)^{2} - 4 (- 5) \cdot 22 = 2399

x_{1, 2} = \frac{- ( - 34 ) \pm 2 399}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 34 ) + 2 399}{2 ( - 5 )}, x_{2} = \frac{- ( - 34 ) - 2 399}{2 ( - 5 )}

x = \frac{- ( - 34 ) + 2 399}{2 ( - 5 )} : - \frac{17 + 399}{5}

x = \frac{- ( - 34 ) - 2 399}{2 ( - 5 )} : \frac{399 - 17}{5}

The solutions to the quadratic equation are:

x = - \frac{17 + 399}{5}, x = \frac{399 - 17}{5}

3 x (x + 2) = 1

\frac{x - 4}{3} + 1 > x + 5

- \frac{27}{2} (\frac{1}{100}) + \frac{27}{2}

- 1 x + 115 < 243

3 t^{2} - 12 t + 9

What are the solutions to the equation -5x(x+6)=4(x-3)-10 ?
The solutions to the equation -5x(x+6)=4(x-3)-10 are x=-(17+sqrt(399))/5 ,x=(sqrt(399)-17)/5
Find the zeros of -5x(x+6)=4(x-3)-10
The zeros of -5x(x+6)=4(x-3)-10 are x=-(17+sqrt(399))/5 ,x=(sqrt(399)-17)/5