What are the solutions to the equation solvefor y,y^2=x^3+3x^2 ?

The solutions to the equation solvefor y,y^2=x^3+3x^2 are y=xsqrt(x+3),y=-xsqrt(x+3)

Find the zeros of solvefor y,y^2=x^3+3x^2

The zeros of solvefor y,y^2=x^3+3x^2 are y=xsqrt(x+3),y=-xsqrt(x+3)

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solve for

y, y^{2} = x^{3} + 3 x^{2}

y = x x + 3, y = - x x + 3

Solution steps

y^{2} = x^{3} + 3 x^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{3} + 3 x^{2}, y = - x^{3} + 3 x^{2}

Simplify

x^{3} + 3 x^{2} : x x + 3

Simplify

- x^{3} + 3 x^{2} : - x x + 3

y = x x + 3, y = - x x + 3

- \frac{1}{5} (- 5)

245

x^{2} - 12 x + 4 = 0

(- 3 + i)^{6}

\frac{x + 1}{( x + 2 ) ( x - 2 )} > 0

What are the solutions to the equation solvefor y,y^2=x^3+3x^2 ?
The solutions to the equation solvefor y,y^2=x^3+3x^2 are y=xsqrt(x+3),y=-xsqrt(x+3)
Find the zeros of solvefor y,y^2=x^3+3x^2
The zeros of solvefor y,y^2=x^3+3x^2 are y=xsqrt(x+3),y=-xsqrt(x+3)