What are the solutions to the equation 3x^2+7x=6 ?

The solutions to the equation 3x^2+7x=6 are x= 2/3 ,x=-3

Find the zeros of 3x^2+7x=6

The zeros of 3x^2+7x=6 are x= 2/3 ,x=-3

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3 x^{2} + 7 x = 6

x = \frac{2}{3}, x = - 3

Decimal Notation

x = 0.66666 \dots, x = - 3

Solution steps

3 x^{2} + 7 x = 6

Move

6

to the left side

3 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 3}, x_{2} = \frac{- 7 - 11}{2 \cdot 3}

x = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 3

(x + 8)^{2} - 23 = - 22

\frac{3 ^{2}}{- 5}

x^{2} - 25 x + 100

2 x^{2} - 7 x + 8 = 0

\frac{1}{4} \leq \frac{6 - x}{12} \leq - \frac{1}{6}

What are the solutions to the equation 3x^2+7x=6 ?
The solutions to the equation 3x^2+7x=6 are x= 2/3 ,x=-3
Find the zeros of 3x^2+7x=6
The zeros of 3x^2+7x=6 are x= 2/3 ,x=-3