What are the solutions to the equation 256=400-16t^2 ?

The solutions to the equation 256=400-16t^2 are t=3,t=-3

Find the zeros of 256=400-16t^2

The zeros of 256=400-16t^2 are t=3,t=-3

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256 = 400 - 16 t^{2}

t = 3, t = - 3

Solution steps

256 = 400 - 16 t^{2}

Switch sides

400 - 16 t^{2} = 256

Move

400

to the right side

- 16 t^{2} = - 144

Divide both sides by

- 16

t^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 9, t = - 9

9 = 3

- 9 = - 3

t = 3, t = - 3

225 - 16 t^{2}

r^{2} + 3 r - 7 = 0

x^{2} - x - 12 \geq 0

15 x^{5} - 72 x^{3} - 108 x

\frac{3 x + 1}{4} - \frac{5 x - 2}{7} = \frac{1}{14}

What are the solutions to the equation 256=400-16t^2 ?
The solutions to the equation 256=400-16t^2 are t=3,t=-3
Find the zeros of 256=400-16t^2
The zeros of 256=400-16t^2 are t=3,t=-3