What are the solutions to the equation 5r^2+8=-12r ?

The solutions to the equation 5r^2+8=-12r are r=-6/5+i 2/5 ,r=-6/5-i 2/5

Find the zeros of 5r^2+8=-12r

The zeros of 5r^2+8=-12r are r=-6/5+i 2/5 ,r=-6/5-i 2/5

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5 r^{2} + 8 = - 12 r

r = - \frac{6}{5} + i \frac{2}{5}, r = - \frac{6}{5} - i \frac{2}{5}

Solution steps

5 r^{2} + 8 = - 12 r

Move

12 r

to the left side

5 r^{2} + 8 + 12 r = 0

Write in the standard form

a x^{2} + b x + c = 0

5 r^{2} + 12 r + 8 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

1 2^{2} - 4 \cdot 5 \cdot 8 : 4 i

r_{1, 2} = \frac{- 12 \pm 4 i}{2 \cdot 5}

Separate the solutions

r_{1} = \frac{- 12 + 4 i}{2 \cdot 5}, r_{2} = \frac{- 12 - 4 i}{2 \cdot 5}

r = \frac{- 12 + 4 i}{2 \cdot 5} : - \frac{6}{5} + i \frac{2}{5}

r = \frac{- 12 - 4 i}{2 \cdot 5} : - \frac{6}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

r = - \frac{6}{5} + i \frac{2}{5}, r = - \frac{6}{5} - i \frac{2}{5}

mn - 2 m + 3 n - 6

g^{2} - 18 g + 45

6 x = 7

lo g_{5} (625)

3 \cdot \frac{2}{3}

What are the solutions to the equation 5r^2+8=-12r ?
The solutions to the equation 5r^2+8=-12r are r=-6/5+i 2/5 ,r=-6/5-i 2/5
Find the zeros of 5r^2+8=-12r
The zeros of 5r^2+8=-12r are r=-6/5+i 2/5 ,r=-6/5-i 2/5