What are the solutions to the equation -3x^2-4x+2=0 ?

The solutions to the equation -3x^2-4x+2=0 are x=-(2+sqrt(10))/3 ,x=(sqrt(10)-2)/3

Find the zeros of -3x^2-4x+2=0

The zeros of -3x^2-4x+2=0 are x=-(2+sqrt(10))/3 ,x=(sqrt(10)-2)/3

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- 3 x^{2} - 4 x + 2 = 0

x = - \frac{2 + 10}{3}, x = \frac{10 - 2}{3}

Decimal Notation

x = - 1.72075 \dots, x = 0.38742 \dots

Solution steps

- 3 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

(- 4)^{2} - 4 (- 3) \cdot 2 = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 ( - 3 )}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 ( - 3 )}

x = \frac{- ( - 4 ) + 2 10}{2 ( - 3 )} : - \frac{2 + 10}{3}

x = \frac{- ( - 4 ) - 2 10}{2 ( - 3 )} : \frac{10 - 2}{3}

The solutions to the quadratic equation are:

x = - \frac{2 + 10}{3}, x = \frac{10 - 2}{3}

x^{2} = 5 x + 14

3 x - 8 = 7 x + 4

∣ x ∣ \leq 6

x + 8 > 5

- 4.9 x^{2} + 10 x + 30 = 0

What are the solutions to the equation -3x^2-4x+2=0 ?
The solutions to the equation -3x^2-4x+2=0 are x=-(2+sqrt(10))/3 ,x=(sqrt(10)-2)/3
Find the zeros of -3x^2-4x+2=0
The zeros of -3x^2-4x+2=0 are x=-(2+sqrt(10))/3 ,x=(sqrt(10)-2)/3