What are the solutions to the equation 2(x-4)^2+6=30 ?

The solutions to the equation 2(x-4)^2+6=30 are x=2sqrt(3)+4,x=-2sqrt(3)+4

Find the zeros of 2(x-4)^2+6=30

The zeros of 2(x-4)^2+6=30 are x=2sqrt(3)+4,x=-2sqrt(3)+4

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2 (x - 4)^{2} + 6 = 30

x = 23 + 4, x = - 23 + 4

Decimal Notation

x = 7.46410 \dots, x = 0.53589 \dots

Solution steps

2 (x - 4)^{2} + 6 = 30

Move

6

to the right side

2 (x - 4)^{2} = 24

Divide both sides by

2

(x - 4)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 12 : x = 23 + 4

Solve

x - 4 = - 12 : x = - 23 + 4

The solutions to the quadratic equation are:

x = 23 + 4, x = - 23 + 4

e^{- \frac{2}{3}}

lo g_{64} (\frac{1}{4})

- 26 = 6 (x - 4) - 8 x

- (\frac{3}{2})^{2} + 4 (- \frac{3}{2})

5 x^{2} - 8 = 18 x

What are the solutions to the equation 2(x-4)^2+6=30 ?
The solutions to the equation 2(x-4)^2+6=30 are x=2sqrt(3)+4,x=-2sqrt(3)+4
Find the zeros of 2(x-4)^2+6=30
The zeros of 2(x-4)^2+6=30 are x=2sqrt(3)+4,x=-2sqrt(3)+4