What are the solutions to the equation 2x^2+3x-3=0 ?

The solutions to the equation 2x^2+3x-3=0 are x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4

Find the zeros of 2x^2+3x-3=0

The zeros of 2x^2+3x-3=0 are x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4

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2 x^{2} + 3 x - 3 = 0

x = \frac{- 3 + 33}{4}, x = \frac{- 3 - 33}{4}

Decimal Notation

x = 0.68614 \dots, x = - 2.18614 \dots

Solution steps

2 x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 3) = 33

x_{1, 2} = \frac{- 3 \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 33}{2 \cdot 2}, x_{2} = \frac{- 3 - 33}{2 \cdot 2}

x = \frac{- 3 + 33}{2 \cdot 2} : \frac{- 3 + 33}{4}

x = \frac{- 3 - 33}{2 \cdot 2} : \frac{- 3 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 33}{4}, x = \frac{- 3 - 33}{4}

2 b^{4} - 6 b^{3} + 6 b^{2} - 2 b

v^{2} - 9 v + 18

3 x + 1 \geq 7

∣ X + 2 ∣ < 1

- \frac{2 π}{3} + 2 π

What are the solutions to the equation 2x^2+3x-3=0 ?
The solutions to the equation 2x^2+3x-3=0 are x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4
Find the zeros of 2x^2+3x-3=0
The zeros of 2x^2+3x-3=0 are x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4