What are the solutions to the equation -16t^2+50t=0 ?

The solutions to the equation -16t^2+50t=0 are t=0,t= 25/8

Find the zeros of -16t^2+50t=0

The zeros of -16t^2+50t=0 are t=0,t= 25/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 t^{2} + 50 t = 0

t = 0, t = \frac{25}{8}

Decimal Notation

t = 0, t = 3.125

Solution steps

- 16 t^{2} + 50 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

5 0^{2} - 4 (- 16) \cdot 0 = 50

t_{1, 2} = \frac{- 50 \pm 50}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 50 + 50}{2 ( - 16 )}, t_{2} = \frac{- 50 - 50}{2 ( - 16 )}

t = \frac{- 50 + 50}{2 ( - 16 )} : 0

t = \frac{- 50 - 50}{2 ( - 16 )} : \frac{25}{8}

The solutions to the quadratic equation are:

t = 0, t = \frac{25}{8}

4 x^{2} - 200 = - 20

2 y^{2} + 10 y = - 7

(x - 1) (x - 2) (x - 6) > 0

9 x^{2} - 9 x + 2

2 (x - 3) = (x - 1) + 7

What are the solutions to the equation -16t^2+50t=0 ?
The solutions to the equation -16t^2+50t=0 are t=0,t= 25/8
Find the zeros of -16t^2+50t=0
The zeros of -16t^2+50t=0 are t=0,t= 25/8