What are the solutions to the equation z^2+14z+40=0 ?

The solutions to the equation z^2+14z+40=0 are z=-4,z=-10

Find the zeros of z^2+14z+40=0

The zeros of z^2+14z+40=0 are z=-4,z=-10

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z^{2} + 14 z + 40 = 0

z = - 4, z = - 10

Solution steps

z^{2} + 14 z + 40 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 40 = 6

z_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 14 + 6}{2 \cdot 1}, z_{2} = \frac{- 14 - 6}{2 \cdot 1}

z = \frac{- 14 + 6}{2 \cdot 1} : - 4

z = \frac{- 14 - 6}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

z = - 4, z = - 10

- \frac{4}{7} + \frac{2}{3}

\frac{x + 1}{2} = - 3

3 (3 - x) \geq 8 + x

y^{2} - 18 y + 81

37

What are the solutions to the equation z^2+14z+40=0 ?
The solutions to the equation z^2+14z+40=0 are z=-4,z=-10
Find the zeros of z^2+14z+40=0
The zeros of z^2+14z+40=0 are z=-4,z=-10