What are the solutions to the equation 3x-x^2=2 ?

The solutions to the equation 3x-x^2=2 are x=1,x=2

Find the zeros of 3x-x^2=2

The zeros of 3x-x^2=2 are x=1,x=2

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3 x - x^{2} = 2

x = 1, x = 2

Solution steps

3 x - x^{2} = 2

Move

2

to the left side

3 x - x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

3^{2} - 4 (- 1) (- 2) = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 ( - 1 )}, x_{2} = \frac{- 3 - 1}{2 ( - 1 )}

x = \frac{- 3 + 1}{2 ( - 1 )} : 1

x = \frac{- 3 - 1}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = 1, x = 2

- \frac{36}{5} + 6

2 x - 6 \leq 3 - 4 x - 12

x^{2} (x^{- 2})

\frac{4 n ^{4} + 5 n ^{3} + 1}{2 n ^{4} - n ^{2} + 3} - 2

- \frac{2}{8}

What are the solutions to the equation 3x-x^2=2 ?
The solutions to the equation 3x-x^2=2 are x=1,x=2
Find the zeros of 3x-x^2=2
The zeros of 3x-x^2=2 are x=1,x=2