What are the solutions to the equation 3x^2+6x-1=0 ?

The solutions to the equation 3x^2+6x-1=0 are x=(-3+2sqrt(3))/3 ,x=-(sqrt(3)+2)/(sqrt(3))

Find the zeros of 3x^2+6x-1=0

The zeros of 3x^2+6x-1=0 are x=(-3+2sqrt(3))/3 ,x=-(sqrt(3)+2)/(sqrt(3))

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3 x^{2} + 6 x - 1 = 0

x = \frac{- 3 + 2 3}{3}, x = - \frac{3 + 2}{3}

Decimal Notation

x = 0.15470 \dots, x = - 2.15470 \dots

Solution steps

3 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 1) = 43

x_{1, 2} = \frac{- 6 \pm 4 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 4 3}{2 \cdot 3}, x_{2} = \frac{- 6 - 4 3}{2 \cdot 3}

x = \frac{- 6 + 4 3}{2 \cdot 3} : \frac{- 3 + 2 3}{3}

x = \frac{- 6 - 4 3}{2 \cdot 3} : - \frac{3 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 3}{3}, x = - \frac{3 + 2}{3}

\frac{3}{8} \cdot \frac{3}{8}

\frac{5}{3} \cdot 2

\frac{\frac{2 x + y}{36}}{\frac{5 x ^{2}}{72}}

4 (0) + 7 y = 3

2 x^{2} + x - 15

What are the solutions to the equation 3x^2+6x-1=0 ?
The solutions to the equation 3x^2+6x-1=0 are x=(-3+2sqrt(3))/3 ,x=-(sqrt(3)+2)/(sqrt(3))
Find the zeros of 3x^2+6x-1=0
The zeros of 3x^2+6x-1=0 are x=(-3+2sqrt(3))/3 ,x=-(sqrt(3)+2)/(sqrt(3))