What are the solutions to the equation 4x^2-8x+5=0 ?

The solutions to the equation 4x^2-8x+5=0 are x=1+i 1/2 ,x=1-i 1/2

Find the zeros of 4x^2-8x+5=0

The zeros of 4x^2-8x+5=0 are x=1+i 1/2 ,x=1-i 1/2

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4 x^{2} - 8 x + 5 = 0

x = 1 + i \frac{1}{2}, x = 1 - i \frac{1}{2}

Solution steps

4 x^{2} - 8 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 5 : 4 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 i}{2 \cdot 4} : 1 + i \frac{1}{2}

x = \frac{- ( - 8 ) - 4 i}{2 \cdot 4} : 1 - i \frac{1}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{1}{2}, x = 1 - i \frac{1}{2}

(x + 3) (x + 2) (x + 5) + (x + 2) (x + 5) + (x + 5)

- 4 < 6 - 2 x \leq 8

- 5 x - 12 \geq 8

3 x^{2} = 30

25 n^{2} - 16

What are the solutions to the equation 4x^2-8x+5=0 ?
The solutions to the equation 4x^2-8x+5=0 are x=1+i 1/2 ,x=1-i 1/2
Find the zeros of 4x^2-8x+5=0
The zeros of 4x^2-8x+5=0 are x=1+i 1/2 ,x=1-i 1/2