What are the solutions to the equation c(c-6)=16 ?

The solutions to the equation c(c-6)=16 are c=8,c=-2

Find the zeros of c(c-6)=16

The zeros of c(c-6)=16 are c=8,c=-2

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c (c - 6) = 16

c = 8, c = - 2

Solution steps

c (c - 6) = 16

Expand

c (c - 6) : c^{2} - 6 c

c^{2} - 6 c = 16

Move

16

to the left side

c^{2} - 6 c - 16 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

c_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, c_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

c = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

c = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

c = 8, c = - 2

\frac{2}{8} + \frac{5}{12}

x^{2} + x = 1

- 10 - n < - 12 or 9 + 4 n \geq 21

∣ 2 x - 1 ∣ \leq 3 - x

2 x^{2} + x = 10

What are the solutions to the equation c(c-6)=16 ?
The solutions to the equation c(c-6)=16 are c=8,c=-2
Find the zeros of c(c-6)=16
The zeros of c(c-6)=16 are c=8,c=-2