What are the solutions to the equation 3x^2-3x-7=0 ?

The solutions to the equation 3x^2-3x-7=0 are x=(3+sqrt(93))/6 ,x=(3-sqrt(93))/6

Find the zeros of 3x^2-3x-7=0

The zeros of 3x^2-3x-7=0 are x=(3+sqrt(93))/6 ,x=(3-sqrt(93))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 3 x - 7 = 0

x = \frac{3 + 93}{6}, x = \frac{3 - 93}{6}

Decimal Notation

x = 2.10727 \dots, x = - 1.10727 \dots

Solution steps

3 x^{2} - 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 7) = 93

x_{1, 2} = \frac{- ( - 3 ) \pm 93}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 93}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 93}{2 \cdot 3}

x = \frac{- ( - 3 ) + 93}{2 \cdot 3} : \frac{3 + 93}{6}

x = \frac{- ( - 3 ) - 93}{2 \cdot 3} : \frac{3 - 93}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 93}{6}, x = \frac{3 - 93}{6}

25 x^{2} - 36 y^{2}

- \frac{5}{6} - 1

\frac{3 x + 1}{4} \geq 1

- - 25

5 (y - 2) - 7 y > - 32

What are the solutions to the equation 3x^2-3x-7=0 ?
The solutions to the equation 3x^2-3x-7=0 are x=(3+sqrt(93))/6 ,x=(3-sqrt(93))/6
Find the zeros of 3x^2-3x-7=0
The zeros of 3x^2-3x-7=0 are x=(3+sqrt(93))/6 ,x=(3-sqrt(93))/6