What are the solutions to the equation 4x^2-12x+9=25 ?

The solutions to the equation 4x^2-12x+9=25 are x=4,x=-1

Find the zeros of 4x^2-12x+9=25

The zeros of 4x^2-12x+9=25 are x=4,x=-1

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4 x^{2} - 12 x + 9 = 25

x = 4, x = - 1

Solution steps

4 x^{2} - 12 x + 9 = 25

Move

25

to the left side

4 x^{2} - 12 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 16) = 20

x_{1, 2} = \frac{- ( - 12 ) \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 20}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 20}{2 \cdot 4}

x = \frac{- ( - 12 ) + 20}{2 \cdot 4} : 4

x = \frac{- ( - 12 ) - 20}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

\frac{2500}{2.53 \cdot 1 0 ^{- 5}}

64 - t^{6}

2 - x + 3 = 2 (x + 1)

8 + 2 m < 2 (m - 6)

\frac{3}{2} + 5

What are the solutions to the equation 4x^2-12x+9=25 ?
The solutions to the equation 4x^2-12x+9=25 are x=4,x=-1
Find the zeros of 4x^2-12x+9=25
The zeros of 4x^2-12x+9=25 are x=4,x=-1