What are the solutions to the equation 18-x^2=39 ?

The solutions to the equation 18-x^2=39 are x=sqrt(21)i,x=-sqrt(21)i

Find the zeros of 18-x^2=39

The zeros of 18-x^2=39 are x=sqrt(21)i,x=-sqrt(21)i

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18 - x^{2} = 39

x = 21 i, x = - 21 i

Solution steps

18 - x^{2} = 39

Move

18

to the right side

- x^{2} = 21

Divide both sides by

- 1

x^{2} = - 21

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 21, x = - - 21

- 21 = 21 i

- - 21 = - 21 i

x = 21 i, x = - 21 i

\frac{3 + 7 i}{i}

5^{2}

\frac{3 x + 5}{3} + \frac{x + 4}{2} \geq \frac{x + 3}{6}

∣ x - 4 ∣ - 4 = 5

9 - 3 x = 1 + x

What are the solutions to the equation 18-x^2=39 ?
The solutions to the equation 18-x^2=39 are x=sqrt(21)i,x=-sqrt(21)i
Find the zeros of 18-x^2=39
The zeros of 18-x^2=39 are x=sqrt(21)i,x=-sqrt(21)i