What are the solutions to the equation r^2+44=-8r ?

The solutions to the equation r^2+44=-8r are r=-4+2sqrt(7)i,r=-4-2sqrt(7)i

Find the zeros of r^2+44=-8r

The zeros of r^2+44=-8r are r=-4+2sqrt(7)i,r=-4-2sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 44 = - 8 r

r = - 4 + 27 i, r = - 4 - 27 i

Solution steps

r^{2} + 44 = - 8 r

Move

8 r

to the left side

r^{2} + 44 + 8 r = 0

Write in the standard form

a x^{2} + b x + c = 0

r^{2} + 8 r + 44 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 44 : 47 i

r_{1, 2} = \frac{- 8 \pm 4 7 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 4 7 i}{2 \cdot 1}, r_{2} = \frac{- 8 - 4 7 i}{2 \cdot 1}

r = \frac{- 8 + 4 7 i}{2 \cdot 1} : - 4 + 27 i

r = \frac{- 8 - 4 7 i}{2 \cdot 1} : - 4 - 27 i

The solutions to the quadratic equation are:

r = - 4 + 27 i, r = - 4 - 27 i

\frac{64}{289}

y, 3 x + 2 y = 6

∣ x + 5 ∣ \geq - 8

∣ x - 2 ∣ - 7 = - 3

x^{4} - 2 x + 1

What are the solutions to the equation r^2+44=-8r ?
The solutions to the equation r^2+44=-8r are r=-4+2sqrt(7)i,r=-4-2sqrt(7)i
Find the zeros of r^2+44=-8r
The zeros of r^2+44=-8r are r=-4+2sqrt(7)i,r=-4-2sqrt(7)i