What are the solutions to the equation x^2+11x=-30 ?

The solutions to the equation x^2+11x=-30 are x=-5,x=-6

Find the zeros of x^2+11x=-30

The zeros of x^2+11x=-30 are x=-5,x=-6

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x^{2} + 11 x = - 30

x = - 5, x = - 6

Solution steps

x^{2} + 11 x = - 30

Move

30

to the left side

x^{2} + 11 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 30 = 1

x_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 1}{2 \cdot 1}, x_{2} = \frac{- 11 - 1}{2 \cdot 1}

x = \frac{- 11 + 1}{2 \cdot 1} : - 5

x = \frac{- 11 - 1}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 5, x = - 6

(4 x + 1) (2 x - 7) = 0

i^{- 203}

m^{2} + 14 m - 51

\frac{20 i}{3 + i}

x^{2} + 7 x - 3 = 0

What are the solutions to the equation x^2+11x=-30 ?
The solutions to the equation x^2+11x=-30 are x=-5,x=-6
Find the zeros of x^2+11x=-30
The zeros of x^2+11x=-30 are x=-5,x=-6