What are the solutions to the equation x^2+15x+7=0 ?

The solutions to the equation x^2+15x+7=0 are x=(-15+sqrt(197))/2 ,x=(-15-sqrt(197))/2

Find the zeros of x^2+15x+7=0

The zeros of x^2+15x+7=0 are x=(-15+sqrt(197))/2 ,x=(-15-sqrt(197))/2

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x^{2} + 15 x + 7 = 0

x = \frac{- 15 + 197}{2}, x = \frac{- 15 - 197}{2}

Decimal Notation

x = - 0.48216 \dots, x = - 14.51783 \dots

Solution steps

x^{2} + 15 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 7 = 197

x_{1, 2} = \frac{- 15 \pm 197}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 197}{2 \cdot 1}, x_{2} = \frac{- 15 - 197}{2 \cdot 1}

x = \frac{- 15 + 197}{2 \cdot 1} : \frac{- 15 + 197}{2}

x = \frac{- 15 - 197}{2 \cdot 1} : \frac{- 15 - 197}{2}

The solutions to the quadratic equation are:

x = \frac{- 15 + 197}{2}, x = \frac{- 15 - 197}{2}

x^{2} - 8 x - 32 = 0

- \frac{23}{2} (\frac{1}{100 0 ^{2}}) + \frac{23}{2}

∣ x + 4 ∣ = ∣ 5 x + 2 ∣

- 7112 + 7

x - \frac{2}{7} = 5

What are the solutions to the equation x^2+15x+7=0 ?
The solutions to the equation x^2+15x+7=0 are x=(-15+sqrt(197))/2 ,x=(-15-sqrt(197))/2
Find the zeros of x^2+15x+7=0
The zeros of x^2+15x+7=0 are x=(-15+sqrt(197))/2 ,x=(-15-sqrt(197))/2