What are the solutions to the equation 3x^2+1=54 ?

The solutions to the equation 3x^2+1=54 are x=sqrt(53/3),x=-sqrt(53/3)

Find the zeros of 3x^2+1=54

The zeros of 3x^2+1=54 are x=sqrt(53/3),x=-sqrt(53/3)

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3 x^{2} + 1 = 54

x = \frac{53}{3}, x = - \frac{53}{3}

Decimal Notation

x = 4.20317 \dots, x = - 4.20317 \dots

Solution steps

3 x^{2} + 1 = 54

Move

1

to the right side

3 x^{2} = 53

Divide both sides by

3

x^{2} = \frac{53}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{53}{3}, x = - \frac{53}{3}

4 y - 4 \geq 20

- 6 a^{4} b^{4} - 6 a^{3} b^{5}

(3 x + 2) 2 = (x + 2) (x - 3)

27 n^{3} - 8

2^{l o g_{2} (8)}

What are the solutions to the equation 3x^2+1=54 ?
The solutions to the equation 3x^2+1=54 are x=sqrt(53/3),x=-sqrt(53/3)
Find the zeros of 3x^2+1=54
The zeros of 3x^2+1=54 are x=sqrt(53/3),x=-sqrt(53/3)