What is x(2x+1)(5x-30)<= 0 ?

The solution to x(2x+1)(5x-30)<= 0 is x<=-1/2 \lor 0<= x<= 6

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x(2x+1)(5x-30)<= 0

x (2 x + 1) (5 x - 30) \leq 0

x \leq - \frac{1}{2} or 0 \leq x \leq 6

Interval Notation

(- \infty, - \frac{1}{2}] \cup [0, 6]

Decimal Notation

x \leq - 0.5 or 0 \leq x \leq 6

Solution steps

x (2 x + 1) (5 x - 30) \leq 0

Rewrite in standard form

2 x^{3} - 11 x^{2} - 6 x \leq 0

Factor

2 x^{3} - 11 x^{2} - 6 x : x (2 x + 1) (x - 6)

x (2 x + 1) (x - 6) \leq 0

Identify the intervals

x \leq - \frac{1}{2} or 0 \leq x \leq 6

\frac{3}{8} + 1

6 (x + 4) = 8 (x - 2)

2 lo g_{3} (4) - (lo g_{3} (2) + lo g_{3} (5))

x^{5} y^{3} - x^{4} y^{4}

\frac{2 π}{1.5}

What is x(2x+1)(5x-30)<= 0 ?
The solution to x(2x+1)(5x-30)<= 0 is x<=-1/2 \lor 0<= x<= 6