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Popular >

|x+1|>= 6

Solution

∣ x + 1 ∣ \geq 6

Solution

x \leq - 7 or x \geq 5

+1

Interval Notation

(- \infty, - 7] \cup [5, \infty)

Solution steps

∣ x + 1 ∣ \geq 6

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x + 1 \leq - 6 or x + 1 \geq 6

x + 1 \leq - 6 or x + 1 \geq 6

x \leq - 7 or x \geq 5

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\frac{1}{8} \cdot \frac{1}{8}

7 x + 35 = 0

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\frac{4 π \cdot 1 0 ^{- 4}}{2 π \cdot 8}

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2 x^{2} + 13 x + 6

factor 8x^3-12x^2+4x factor

8 x^{3} - 12 x^{2} + 4 x

Frequently Asked Questions (FAQ)

What is |x+1|>= 6 ?
The solution to |x+1|>= 6 is x<=-7\lor x>= 5