What are the solutions to the equation x^2+8x+64=12 ?

The solutions to the equation x^2+8x+64=12 are x=-4+6i,x=-4-6i

Find the zeros of x^2+8x+64=12

The zeros of x^2+8x+64=12 are x=-4+6i,x=-4-6i

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x^{2} + 8 x + 64 = 12

x = - 4 + 6 i, x = - 4 - 6 i

Solution steps

x^{2} + 8 x + 64 = 12

Move

12

to the left side

x^{2} + 8 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 52 : 12 i

x_{1, 2} = \frac{- 8 \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 12 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 12 i}{2 \cdot 1}

x = \frac{- 8 + 12 i}{2 \cdot 1} : - 4 + 6 i

x = \frac{- 8 - 12 i}{2 \cdot 1} : - 4 - 6 i

The solutions to the quadratic equation are:

x = - 4 + 6 i, x = - 4 - 6 i

56 \cdot 83

4 x^{2} + (5 - 2 x)^{2} = 17

\frac{2}{1} = \frac{U}{25}

\frac{2}{3} x + 5 = 1

\frac{1}{12} \div (\frac{1}{8} - \frac{1}{2})

What are the solutions to the equation x^2+8x+64=12 ?
The solutions to the equation x^2+8x+64=12 are x=-4+6i,x=-4-6i
Find the zeros of x^2+8x+64=12
The zeros of x^2+8x+64=12 are x=-4+6i,x=-4-6i