What are the solutions to the equation x^2+9x-10=0 ?

The solutions to the equation x^2+9x-10=0 are x=1,x=-10

Find the zeros of x^2+9x-10=0

The zeros of x^2+9x-10=0 are x=1,x=-10

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x^{2} + 9 x - 10 = 0

x = 1, x = - 10

Solution steps

x^{2} + 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 10) = 11

x_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 11}{2 \cdot 1}, x_{2} = \frac{- 9 - 11}{2 \cdot 1}

x = \frac{- 9 + 11}{2 \cdot 1} : 1

x = \frac{- 9 - 11}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 1, x = - 10

7 a^{4} b \cdot (- 3 a^{5} b^{6})^{2}

4 x^{2} + 16 x = 20

- 8 (n - 83) = - 40

(2^{- 4} \cdot z^{- 3})^{5}

\frac{- 15 k ^{2}}{15 k ^{3} + 45 k ^{2}}

What are the solutions to the equation x^2+9x-10=0 ?
The solutions to the equation x^2+9x-10=0 are x=1,x=-10
Find the zeros of x^2+9x-10=0
The zeros of x^2+9x-10=0 are x=1,x=-10