What are the solutions to the equation 3x^2-2x+1=0 ?

The solutions to the equation 3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3

Find the zeros of 3x^2-2x+1=0

The zeros of 3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3

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3 x^{2} - 2 x + 1 = 0

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

Solution steps

3 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 1 : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 3} : \frac{1}{3} + i \frac{2}{3}

x = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 3} : \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{2}{3}, x = \frac{1}{3} - i \frac{2}{3}

21 k^{2} + 4 k - 1

x^{2} + \frac{1}{6} x - \frac{1}{6} = 0

(8 x^{6})^{- \frac{2}{3}}

ln (2) \cdot ln (2)

4 (x + 2) = 6 x + 10

What are the solutions to the equation 3x^2-2x+1=0 ?
The solutions to the equation 3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3
Find the zeros of 3x^2-2x+1=0
The zeros of 3x^2-2x+1=0 are x= 1/3+i(sqrt(2))/3 ,x= 1/3-i(sqrt(2))/3