What are the solutions to the equation 5-8x=3x^2-12x+3 ?

The solutions to the equation 5-8x=3x^2-12x+3 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3

Find the zeros of 5-8x=3x^2-12x+3

The zeros of 5-8x=3x^2-12x+3 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3

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5 - 8 x = 3 x^{2} - 12 x + 3

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

Decimal Notation

x = 1.72075 \dots, x = - 0.38742 \dots

Solution steps

5 - 8 x = 3 x^{2} - 12 x + 3

Switch sides

3 x^{2} - 12 x + 3 = 5 - 8 x

Move

8 x

to the left side

3 x^{2} - 4 x + 3 = 5

Move

5

to the left side

3 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 2) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 3} : \frac{2 + 10}{3}

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 3} : \frac{2 - 10}{3}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

\frac{- 3 + 11 i}{3 + 2 i}

24 + 2 x - x^{2} = 0

3 x (x - 2) = 9 x^{2} - 11 x

593.7 x - 57 x^{2} = 1282.64 + 677.64

5 x^{2} \cdot x^{2}

What are the solutions to the equation 5-8x=3x^2-12x+3 ?
The solutions to the equation 5-8x=3x^2-12x+3 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3
Find the zeros of 5-8x=3x^2-12x+3
The zeros of 5-8x=3x^2-12x+3 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3