What are the solutions to the equation (x+5)^2=81 ?

The solutions to the equation (x+5)^2=81 are x=4,x=-14

Find the zeros of (x+5)^2=81

The zeros of (x+5)^2=81 are x=4,x=-14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 5)^{2} = 81

x = 4, x = - 14

Solution steps

(x + 5)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 81 : x = 4

Solve

x + 5 = - 81 : x = - 14

The solutions to the quadratic equation are:

x = 4, x = - 14

(3 m^{3} - \frac{1}{2} y) (3 m^{3} - \frac{1}{2} y)

t^{2} - 5 t = - 4

9 (\frac{10}{13} - \frac{1}{3})

- 2 ∣ x - 3 ∣ \geq - 4

\frac{3 x - 1}{4} = 5

What are the solutions to the equation (x+5)^2=81 ?
The solutions to the equation (x+5)^2=81 are x=4,x=-14
Find the zeros of (x+5)^2=81
The zeros of (x+5)^2=81 are x=4,x=-14