What are the solutions to the equation -6+3x-9x^2=-16 ?

The solutions to the equation -6+3x-9x^2=-16 are x=-(-1+sqrt(41))/6 ,x=(1+sqrt(41))/6

Find the zeros of -6+3x-9x^2=-16

The zeros of -6+3x-9x^2=-16 are x=-(-1+sqrt(41))/6 ,x=(1+sqrt(41))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 6 + 3 x - 9 x^{2} = - 16

x = - \frac{- 1 + 41}{6}, x = \frac{1 + 41}{6}

Decimal Notation

x = - 0.90052 \dots, x = 1.23385 \dots

Solution steps

- 6 + 3 x - 9 x^{2} = - 16

Move

16

to the left side

- 9 x^{2} + 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 9 ) \cdot 10}{2 ( - 9 )}

3^{2} - 4 (- 9) \cdot 10 = 341

x_{1, 2} = \frac{- 3 \pm 3 41}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 3 + 3 41}{2 ( - 9 )}, x_{2} = \frac{- 3 - 3 41}{2 ( - 9 )}

x = \frac{- 3 + 3 41}{2 ( - 9 )} : - \frac{- 1 + 41}{6}

x = \frac{- 3 - 3 41}{2 ( - 9 )} : \frac{1 + 41}{6}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 41}{6}, x = \frac{1 + 41}{6}

(\frac{3}{2})^{7} - 6

∣ 5 x ∣ = 4

- 6 \leq 6 x + 3 \leq 21

x^{2} - 2 x - 7 < 1

2 x - 3 < 8

What are the solutions to the equation -6+3x-9x^2=-16 ?
The solutions to the equation -6+3x-9x^2=-16 are x=-(-1+sqrt(41))/6 ,x=(1+sqrt(41))/6
Find the zeros of -6+3x-9x^2=-16
The zeros of -6+3x-9x^2=-16 are x=-(-1+sqrt(41))/6 ,x=(1+sqrt(41))/6