What are the solutions to the equation 5v^2-27v+4=-6 ?

The solutions to the equation 5v^2-27v+4=-6 are v=5,v= 2/5

Find the zeros of 5v^2-27v+4=-6

The zeros of 5v^2-27v+4=-6 are v=5,v= 2/5

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5 v^{2} - 27 v + 4 = - 6

v = 5, v = \frac{2}{5}

Decimal Notation

v = 5, v = 0.4

Solution steps

5 v^{2} - 27 v + 4 = - 6

Move

6

to the left side

5 v^{2} - 27 v + 10 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

(- 27)^{2} - 4 \cdot 5 \cdot 10 = 23

v_{1, 2} = \frac{- ( - 27 ) \pm 23}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 27 ) + 23}{2 \cdot 5}, v_{2} = \frac{- ( - 27 ) - 23}{2 \cdot 5}

v = \frac{- ( - 27 ) + 23}{2 \cdot 5} : 5

v = \frac{- ( - 27 ) - 23}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

v = 5, v = \frac{2}{5}

2 x^{2} + x \geq 15

155

4 x + 8 - 3 x = 5

1^{\frac{2}{3}}

(x - 5)^{2} = 7

What are the solutions to the equation 5v^2-27v+4=-6 ?
The solutions to the equation 5v^2-27v+4=-6 are v=5,v= 2/5
Find the zeros of 5v^2-27v+4=-6
The zeros of 5v^2-27v+4=-6 are v=5,v= 2/5