What is ((2x)/(3(x^2)^{2/3)})^2 ?

The solution to ((2x)/(3(x^2)^{2/3)})^2 is 4/(9x^{2/3)}

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simplify ((2x)/(3(x^2)^{2/3)})^2

simplify

(\frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}})^{2}

\frac{4}{9 x ^{\frac{2}{3}}}

Solution steps

(\frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x ) ^{2}}{( 3 ( x ^{2} ) ^{\frac{2}{3}} ) ^{2}}

Simplify

(2 x)^{2} : 4 x^{2}

= \frac{4 x ^{2}}{( 3 ( x ^{2} ) ^{\frac{2}{3}} ) ^{2}}

Simplify

(3 (x^{2})^{\frac{2}{3}})^{2} : 9 x^{\frac{8}{3}}

= \frac{4 x ^{2}}{9 x ^{\frac{8}{3}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{2}}{x ^{\frac{8}{3}}} = \frac{1}{x ^{\frac{8}{3} - 2}}

= \frac{4}{9 x ^{\frac{8}{3} - 2}}

Subtract the numbers:

\frac{8}{3} - 2 = \frac{2}{3}

= \frac{4}{9 x ^{\frac{2}{3}}}

2 j^{2} + 9 j + 7

x - 7.6 (0.9 x + 1) \leq 5.6 (1 + 1.1 x)

\frac{1}{x - 4} \geq \frac{3}{x + 1}

2 x^{2} + 8 x - 5 = 0

What is ((2x)/(3(x^2)^{2/3)})^2 ?
The solution to ((2x)/(3(x^2)^{2/3)})^2 is 4/(9x^{2/3)}