What are the solutions to the equation 1=9x^2+8x ?

The solutions to the equation 1=9x^2+8x are x= 1/9 ,x=-1

Find the zeros of 1=9x^2+8x

The zeros of 1=9x^2+8x are x= 1/9 ,x=-1

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1 = 9 x^{2} + 8 x

x = \frac{1}{9}, x = - 1

Decimal Notation

x = 0.11111 \dots, x = - 1

Solution steps

1 = 9 x^{2} + 8 x

Switch sides

9 x^{2} + 8 x = 1

Move

1

to the left side

9 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

8^{2} - 4 \cdot 9 (- 1) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 9}, x_{2} = \frac{- 8 - 10}{2 \cdot 9}

x = \frac{- 8 + 10}{2 \cdot 9} : \frac{1}{9}

x = \frac{- 8 - 10}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{9}, x = - 1

∣ 3 x - 8 ∣ < 1

\frac{14.3}{8} (- \frac{16}{15})

9 y^{2} - 1

x^{2} - 4 x = 10

What are the solutions to the equation 1=9x^2+8x ?
The solutions to the equation 1=9x^2+8x are x= 1/9 ,x=-1
Find the zeros of 1=9x^2+8x
The zeros of 1=9x^2+8x are x= 1/9 ,x=-1