What are the solutions to the equation -x^2+4x+6=0 ?

The solutions to the equation -x^2+4x+6=0 are x=2-sqrt(10),x=2+sqrt(10)

Find the zeros of -x^2+4x+6=0

The zeros of -x^2+4x+6=0 are x=2-sqrt(10),x=2+sqrt(10)

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- x^{2} + 4 x + 6 = 0

x = 2 - 10, x = 2 + 10

Decimal Notation

x = - 1.16227 \dots, x = 5.16227 \dots

Solution steps

- x^{2} + 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 6 = 210

x_{1, 2} = \frac{- 4 \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 10}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 10}{2 ( - 1 )}

x = \frac{- 4 + 2 10}{2 ( - 1 )} : 2 - 10

x = \frac{- 4 - 2 10}{2 ( - 1 )} : 2 + 10

The solutions to the quadratic equation are:

x = 2 - 10, x = 2 + 10

375 + 212

\frac{n - 5}{6} + \frac{n + 3}{7} = \frac{11}{21}

3 (3 x - 2) = 39

8 p + 10 > - 5 p - 1

4 x^{2} (x^{2} - 81) \leq 0

What are the solutions to the equation -x^2+4x+6=0 ?
The solutions to the equation -x^2+4x+6=0 are x=2-sqrt(10),x=2+sqrt(10)
Find the zeros of -x^2+4x+6=0
The zeros of -x^2+4x+6=0 are x=2-sqrt(10),x=2+sqrt(10)