What are the solutions to the equation 3/2 x^2+11=71 ?

The solutions to the equation 3/2 x^2+11=71 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of 3/2 x^2+11=71

The zeros of 3/2 x^2+11=71 are x=2sqrt(10),x=-2sqrt(10)

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\frac{3}{2} x^{2} + 11 = 71

x = 210, x = - 210

Decimal Notation

x = 6.32455 \dots, x = - 6.32455 \dots

Solution steps

\frac{3}{2} x^{2} + 11 = 71

Move

11

to the right side

\frac{3}{2} x^{2} = 60

Multiply both sides by

2

3 x^{2} = 120

Divide both sides by

3

x^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

a x + a y + x + y

(5 - 3 i)^{2}

(\frac{11}{4})^{2}

a^{3} + b^{3}

\frac{8 m ^{3} + 64}{4 m ^{2} + 34 m + 52}

What are the solutions to the equation 3/2 x^2+11=71 ?
The solutions to the equation 3/2 x^2+11=71 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of 3/2 x^2+11=71
The zeros of 3/2 x^2+11=71 are x=2sqrt(10),x=-2sqrt(10)