What are the solutions to the equation 2x^2-3=x ?

The solutions to the equation 2x^2-3=x are x= 3/2 ,x=-1

Find the zeros of 2x^2-3=x

The zeros of 2x^2-3=x are x= 3/2 ,x=-1

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2 x^{2} - 3 = x

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

2 x^{2} - 3 = x

Move

x

to the left side

2 x^{2} - 3 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

\frac{3}{15}

1 \cdot 1 0^{6}

3 - ∣ x - 1 ∣ > 0

∣ x ∣ - ∣ x + 2 ∣ = 5

x^{3} + 3 x^{2} - 2

What are the solutions to the equation 2x^2-3=x ?
The solutions to the equation 2x^2-3=x are x= 3/2 ,x=-1
Find the zeros of 2x^2-3=x
The zeros of 2x^2-3=x are x= 3/2 ,x=-1