What are the solutions to the equation (x)^2+(21)^2=(29)^2 ?

The solutions to the equation (x)^2+(21)^2=(29)^2 are x=20,x=-20

Find the zeros of (x)^2+(21)^2=(29)^2

The zeros of (x)^2+(21)^2=(29)^2 are x=20,x=-20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x)^{2} + (21)^{2} = (29)^{2}

x = 20, x = - 20

Solution steps

x^{2} + (21)^{2} = (29)^{2}

Expand

x^{2} + 2 1^{2} : x^{2} + 441

Expand

2 9^{2} : 841

x^{2} + 441 = 841

Move

441

to the right side

x^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 400, x = - 400

400 = 20

- 400 = - 20

x = 20, x = - 20

(5 x - 2)^{2} - 6 = 0

- 2 \cdot 3^{- (2)}

2 x^{2} + 8 = 0

8 r^{3} + 1

- 5 \cdot \frac{1}{8}

What are the solutions to the equation (x)^2+(21)^2=(29)^2 ?
The solutions to the equation (x)^2+(21)^2=(29)^2 are x=20,x=-20
Find the zeros of (x)^2+(21)^2=(29)^2
The zeros of (x)^2+(21)^2=(29)^2 are x=20,x=-20