What are the solutions to the equation x^2-5x=7 ?

The solutions to the equation x^2-5x=7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2

Find the zeros of x^2-5x=7

The zeros of x^2-5x=7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x = 7

x = \frac{5 + 53}{2}, x = \frac{5 - 53}{2}

Decimal Notation

x = 6.14005 \dots, x = - 1.14005 \dots

Solution steps

x^{2} - 5 x = 7

Move

7

to the left side

x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 7) = 53

x_{1, 2} = \frac{- ( - 5 ) \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 53}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 53}{2 \cdot 1}

x = \frac{- ( - 5 ) + 53}{2 \cdot 1} : \frac{5 + 53}{2}

x = \frac{- ( - 5 ) - 53}{2 \cdot 1} : \frac{5 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 53}{2}, x = \frac{5 - 53}{2}

4 < x \leq 6

c^{2} + 10 c + 21 = 0

2 x - 3 = 1 - 2 x + x^{2}

1872

2 (5 x - 2) = 10 x + 4

What are the solutions to the equation x^2-5x=7 ?
The solutions to the equation x^2-5x=7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2
Find the zeros of x^2-5x=7
The zeros of x^2-5x=7 are x=(5+sqrt(53))/2 ,x=(5-sqrt(53))/2