What are the solutions to the equation n^2+2n-2=0 ?

The solutions to the equation n^2+2n-2=0 are n=-1+sqrt(3),n=-1-sqrt(3)

Find the zeros of n^2+2n-2=0

The zeros of n^2+2n-2=0 are n=-1+sqrt(3),n=-1-sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 2 n - 2 = 0

n = - 1 + 3, n = - 1 - 3

Decimal Notation

n = 0.73205 \dots, n = - 2.73205 \dots

Solution steps

n^{2} + 2 n - 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

n_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, n_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

n = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

n = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

n = - 1 + 3, n = - 1 - 3

x^{12} y^{18} + 1

5 x^{2} - 20 y^{2}

\frac{1}{2} > - 2 x + \frac{7}{2}

∣ 12 ∣

2 k^{2} - 14 k - 60

What are the solutions to the equation n^2+2n-2=0 ?
The solutions to the equation n^2+2n-2=0 are n=-1+sqrt(3),n=-1-sqrt(3)
Find the zeros of n^2+2n-2=0
The zeros of n^2+2n-2=0 are n=-1+sqrt(3),n=-1-sqrt(3)