What are the solutions to the equation 6x^2-19x+19=5 ?

The solutions to the equation 6x^2-19x+19=5 are x=2,x= 7/6

Find the zeros of 6x^2-19x+19=5

The zeros of 6x^2-19x+19=5 are x=2,x= 7/6

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6 x^{2} - 19 x + 19 = 5

x = 2, x = \frac{7}{6}

Decimal Notation

x = 2, x = 1.16666 \dots

Solution steps

6 x^{2} - 19 x + 19 = 5

Move

5

to the left side

6 x^{2} - 19 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 6 \cdot 14}{2 \cdot 6}

(- 19)^{2} - 4 \cdot 6 \cdot 14 = 5

x_{1, 2} = \frac{- ( - 19 ) \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 5}{2 \cdot 6}, x_{2} = \frac{- ( - 19 ) - 5}{2 \cdot 6}

x = \frac{- ( - 19 ) + 5}{2 \cdot 6} : 2

x = \frac{- ( - 19 ) - 5}{2 \cdot 6} : \frac{7}{6}

The solutions to the quadratic equation are:

x = 2, x = \frac{7}{6}

6 x = 3 x + 9

2 n > 20

- 3 (w + 5) + 33 \leq 3 (6 - w)

\frac{x - 2}{3} \leq \frac{3 + x}{2}

x^{2} - 3 \cdot x + 2 > 0

What are the solutions to the equation 6x^2-19x+19=5 ?
The solutions to the equation 6x^2-19x+19=5 are x=2,x= 7/6
Find the zeros of 6x^2-19x+19=5
The zeros of 6x^2-19x+19=5 are x=2,x= 7/6