What are the solutions to the equation -2x^2-9x+5=0 ?

The solutions to the equation -2x^2-9x+5=0 are x=-5,x= 1/2

Find the zeros of -2x^2-9x+5=0

The zeros of -2x^2-9x+5=0 are x=-5,x= 1/2

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- 2 x^{2} - 9 x + 5 = 0

x = - 5, x = \frac{1}{2}

Decimal Notation

x = - 5, x = 0.5

Solution steps

- 2 x^{2} - 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 9)^{2} - 4 (- 2) \cdot 5 = 11

x_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 11}{2 ( - 2 )}, x_{2} = \frac{- ( - 9 ) - 11}{2 ( - 2 )}

x = \frac{- ( - 9 ) + 11}{2 ( - 2 )} : - 5

x = \frac{- ( - 9 ) - 11}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - 5, x = \frac{1}{2}

\frac{- 2}{x - 1} > 0

5 + \frac{4}{3}

\frac{5}{3} + \frac{2}{4}

f + g

\frac{5}{5 + 2}

What are the solutions to the equation -2x^2-9x+5=0 ?
The solutions to the equation -2x^2-9x+5=0 are x=-5,x= 1/2
Find the zeros of -2x^2-9x+5=0
The zeros of -2x^2-9x+5=0 are x=-5,x= 1/2