What are the solutions to the equation 5x^2-40x-75=0 ?

The solutions to the equation 5x^2-40x-75=0 are x=4+sqrt(31),x=4-sqrt(31)

Find the zeros of 5x^2-40x-75=0

The zeros of 5x^2-40x-75=0 are x=4+sqrt(31),x=4-sqrt(31)

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5 x^{2} - 40 x - 75 = 0

x = 4 + 31, x = 4 - 31

Decimal Notation

x = 9.56776 \dots, x = - 1.56776 \dots

Solution steps

5 x^{2} - 40 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 5 ( - 75 )}{2 \cdot 5}

(- 40)^{2} - 4 \cdot 5 (- 75) = 1031

x_{1, 2} = \frac{- ( - 40 ) \pm 10 31}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 10 31}{2 \cdot 5}, x_{2} = \frac{- ( - 40 ) - 10 31}{2 \cdot 5}

x = \frac{- ( - 40 ) + 10 31}{2 \cdot 5} : 4 + 31

x = \frac{- ( - 40 ) - 10 31}{2 \cdot 5} : 4 - 31

The solutions to the quadratic equation are:

x = 4 + 31, x = 4 - 31

1 6^{3}

\frac{( a ^{4} - b ^{4} )}{( a - b )}

\frac{8 ! 7 !}{9 ! 5 !}

∣ x ∣ = - 14

6 n^{2} = 9 n

What are the solutions to the equation 5x^2-40x-75=0 ?
The solutions to the equation 5x^2-40x-75=0 are x=4+sqrt(31),x=4-sqrt(31)
Find the zeros of 5x^2-40x-75=0
The zeros of 5x^2-40x-75=0 are x=4+sqrt(31),x=4-sqrt(31)